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Four dice, each numbered in the usual way from 1 to 6, are colored white, red, green and blue respectively. After casting them a boy scored in the following way. To the white numbered he adds twice the red and blue numbered and then subtract the green numbered. Assume that the boy casts the dice large number of times; calculate the mean and variance of scores. I have no idea ... Can anybody help ASAP
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@ganeshie8
Yea @Loser66 W + 2(B+R) - G is our variable
@Loser66 Mean is 7/2 ... I've dont it
*done
\[E(W)=\sum_{X=1}^{6} x _{i} P _{x i} = \frac{ 1 }{ 6} \sum_{x=1}^{6} x = \frac{ 21 }{ 6}\]
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This is mean for white
so 7/2 + 2( 7/2 + 7/2 ) -7/2
Lol it is also above my head... My friend told me how to do it :P
Probability sucks Lol
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