There are 4 blue marbles and 3 red marbles in a bag. You randomly pick one marble, keep it, and then pick a second marble. What is the probability that you will pick two blue marbles?
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OpenStudy (anonymous):
2/7 ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
8/21 ? @satellite73
OpenStudy (anonymous):
oh there you are
OpenStudy (anonymous):
what is the probability that the first one selected is blue?
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OpenStudy (anonymous):
4/7 ?
@satellite73
OpenStudy (anonymous):
yes
now that marble is in your pocket
what is the probability that the second marble selected is blue now that one blue marble is gone?
OpenStudy (anonymous):
oh heavens, i see you had the right answer to begin with!!
OpenStudy (anonymous):
the same right because everytime i take one out i put it back in there ? @satellite73
OpenStudy (anonymous):
and me, like a dope, said "no"
so sorry
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OpenStudy (anonymous):
no now it is \(\frac{3}{6}=\frac{1}{2}\) because one blue marble is gone and there are now 3 blue and 6 total
so you were right
\[\frac{4}{7}\times \frac{1}{2}=\frac{2}{7}\]
OpenStudy (anonymous):
you were right, sorry to waste your time
i misread blue for red
you had it on the first try
OpenStudy (anonymous):
its cool so its 2/7
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
thank you
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