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Mathematics 16 Online
OpenStudy (anonymous):

Figuring out equations for parallel and perpendicular? Ill post the problem below! Fan + Medal!

OpenStudy (anonymous):

OpenStudy (anonymous):

4

OpenStudy (haseeb96):

y=mx +b as u know this is slope intercept form when we compare it with the equation of question that is y=-5/4 x -5

OpenStudy (anonymous):

y=-4/5x=4 i believe if perpendicular

OpenStudy (anonymous):

y=-5/4x+4 is parallel

OpenStudy (anonymous):

^^+4*

OpenStudy (anonymous):

did this help at all?

OpenStudy (anonymous):

thats what i said lol

OpenStudy (anonymous):

? all you said was "4"

OpenStudy (haseeb96):

here m is called slope while b is called y intercept

OpenStudy (haseeb96):

now when we compare these two slope intercept equations we got slope that is m = - 5/4 while the question is saying that u need to an equation of a line which should be perpendicular

OpenStudy (haseeb96):

so we use the equation of slope for perpendicular m x m' = -1 since m =-5/4 -5/4 x m' = -1 m' = -1 x -4/5 m'=4/5 so the slope for perpendicular line is m' = 4/5 now the point is given in the question (x',y')= (-4,4) now use this formula and get the equation of perpendicular line y - y' = m' (x -x') this is the formula now just put the slope and point in this formula and get the equation

OpenStudy (haseeb96):

@heythatsness

OpenStudy (haseeb96):

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