Solve the equation by a method of your choice:
6x2 + 5x + 1 = 0
If there are two solutions, separate the solutions by a comma.
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OpenStudy (anonymous):
@TheSmartOne
OpenStudy (noelgreco):
Use grouping of the linear term
OpenStudy (mrnood):
(ax+b)(cx+d)
you can see that b and c MUST be 1 to multiply out to 1
so (ax + 1)(bx+1)
find a and b so ab=6 and a+b = 5
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so what do i do 6 and 5
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OpenStudy (anonymous):
@BunnyBree
OpenStudy (mrnood):
I have shown you haow to factoise the equagtion, and shown that the constant term must be 1 in each bracket
so
(ax + 1)(bx+1)=6x2 + 5x + 1
so a*b =6
a+b = 5
find the values of a and b (you might just need to think about it for a minute...)
OpenStudy (anonymous):
ok um i dont know
OpenStudy (mrnood):
OK
think of 2 numbers that multiply toghether to make 6
(there are only 2 possible pairs - one of them is 1 and 6)
think of the other one.
Do those two numbers add up to 5?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
@AriPotta
OpenStudy (mrnood):
what are the other 2 numbers that multiply to make 6 (other than 1 *6)?