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OpenStudy (anonymous):
|dw:1416907469988:dw|
OpenStudy (anonymous):
@campbell_st
OpenStudy (fibonaccichick666):
you should really watch some khanacademy.org videos so you understand the material
OpenStudy (anonymous):
well i dont have time for that
OpenStudy (campbell_st):
I'd find h as my 1st step using the left hand right triangle... angle 45 and hypotenuse 8.
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then when you have h look at the right hand right triangle and you can find both x and y using trig ratios.
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OpenStudy (anonymous):
@Mariam.A can u help on this one?
OpenStudy (anonymous):
u there ??
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
ok do you know the sine rule????
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
can u make this quick, i need to go..
OpenStudy (anonymous):
ok sine rule states \[\frac{ a }{ sinA }=\frac{ b }{ sinb }\]
OpenStudy (anonymous):
so looking at the little triangle with side 8
if a=8 and sinA is its opposite angle sinA=sin90
and b=h like campbell labelled and its opposite angle sinB=sin45
OpenStudy (anonymous):
\[\frac{ 8 }{ \sin90 }=\frac{ h }{ \sin45 }\]
OpenStudy (anonymous):
ok so what next..
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