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Mathematics 14 Online
OpenStudy (anonymous):

Find the value of x and y.

OpenStudy (anonymous):

|dw:1416907469988:dw|

OpenStudy (anonymous):

@campbell_st

OpenStudy (fibonaccichick666):

you should really watch some khanacademy.org videos so you understand the material

OpenStudy (anonymous):

well i dont have time for that

OpenStudy (campbell_st):

I'd find h as my 1st step using the left hand right triangle... angle 45 and hypotenuse 8. |dw:1416907538525:dw| then when you have h look at the right hand right triangle and you can find both x and y using trig ratios.

OpenStudy (anonymous):

@Mariam.A can u help on this one?

OpenStudy (anonymous):

u there ??

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

ok do you know the sine rule????

OpenStudy (anonymous):

no

OpenStudy (anonymous):

can u make this quick, i need to go..

OpenStudy (anonymous):

ok sine rule states \[\frac{ a }{ sinA }=\frac{ b }{ sinb }\]

OpenStudy (anonymous):

so looking at the little triangle with side 8 if a=8 and sinA is its opposite angle sinA=sin90 and b=h like campbell labelled and its opposite angle sinB=sin45

OpenStudy (anonymous):

\[\frac{ 8 }{ \sin90 }=\frac{ h }{ \sin45 }\]

OpenStudy (anonymous):

ok so what next..

OpenStudy (fibonaccichick666):

solve for h

OpenStudy (anonymous):

do we multiply

OpenStudy (anonymous):

you can solve for h by cross multiplying

OpenStudy (anonymous):

90h/360

OpenStudy (anonymous):

|dw:1416974402448:dw|

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