Question

What is the standard form of the equation for this circle?

Answer 1

General equation for a circle is \((x-h)^2+(y-k)^2+r^2\), where \((h, k)\) is center point and \(r\) is radius.

Answer 2

So my radius is 5.5?

Answer 3

geerky42 has a small typo

\[(x-h)^2+(y-k)^2=r^2\]

Answer 4

@geerky42

Answer 5

But that's my radius right?

Answer 6

Yes.

Answer 7

So it's C!

Answer 8

Actually it's B:

\((x-(4))^2+(y-(-5))^2=(5.5)^2 \Longrightarrow (x-4)^2+(y+5)^2=30.25\)

Answer 9

Sorry, I just jumped to the the first one where I saw #0.25 I should look closer