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if cos theta=-5/13 and theta is greater than or equal to 0 and less then or equal to 2pi, determine a) Tan theta b) sec theta
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\[\cos \theta=\frac{ -5 }{ 13 }, 0\le \theta \le2\pi\] find: \[a)\tan \theta\] \[b)\sec\theta\]
What I think it should be for tan theta|dw:1416949399066:dw| tan theta= 12/-5?
Sec is just 1/ Cos so Sec theta = 13/-5
is my answer correct for tan theta cuz the book got a different answer
Tan = sin / cos Since the sin is Opposite/Hypotenuse Sin = 12/13 Cos is Adjacent/Hypotenuse so it is -5/13 12/13 * 13/-5 = -12/5 = 12/-5 so yes you did get the correct answer for tan theta
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the book says its 12/13
for tan theta
oh well i guess they messed up.
Yeah I think they meant to say that Sin theta = 12/13
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