Question

solve 2x^2-4x+7=0 by using the quadratic formula

Answer 1

\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=2,b=-4,c=7\] gives
\[\frac{4\pm\sqrt{(-4)^2-4\times 2\times 7}}{2\times 2}\] it is arithmetic from there on in

Answer 2

@satellite73 what would be the answer

Answer 3

you only need to do the arithmetic under the radical
what do you get ?

Answer 4

so 2x2=4? @satellite73

Answer 5

yes in the denominator

Answer 6

how about \((-4)^2-4\times 2\times 7\)?

Answer 7

6

Answer 8

@satellite73

Answer 9

is it a,b,c? @satellite73

Answer 10

check the pic i posted and whats the answer there

Answer 11

I think, that is the answer

Answer 12

thanks