Question

one leg of a right triangle is 2 more than twice the other. The hypotenuse is 13 meters. what is the lengths of the two legs

Answer 1

Picture a triangle like this:

They gave you hypotenuse = 13
c = 13

One leg is 2 more than twice the other:
a = 2+2x

The "other" leg:
b = x

Use the Pythagorean theorem to solve for x with the a, b and c values.

\[a ^{2} + b ^{2} = c ^{2}\]

Answer 2

Ok that you!! Got it So would I set it up as 2+2x+x=13

Answer 3

Set it up like this:
\[(x+2x)^{2} + x^{2} = 13^{2}\]

Answer 4

sorry i mean \[(2+2x)^{2} + x^{2} = 13^{2}\]

Answer 5

Got it.. Ok thank you!!

Answer 6

Sure :)