Question

the domain and range in a radical expression y=x^2 +2

Answer 1

x = 27

Answer 2

where is the radical exactly?

Answer 3

\[y=\sqrt{x^2+2}\]?

Answer 4

the range is the set of y values
for any value of x then y is positive
given y = x^2 + 2
then Y-2 = x^2
x = square root of (Y -2 )
for square root positive and negative values
also (y-2) must be positive

Answer 5

@Ada1959

The vertex of the parabola which is the equation of y= x^2 + 2 is (0 , 2).

Because the coefficient of the x^2 term is positive, the parabola opens upward.

Therefore the smallest y-value possible is 2. The range is {all y > or = to 2}.

There is no reason to exclude any value from the set of possible x-values.

The domain is the set of real numbers.