Question

Check my stuff (Picture attached)

Answer 1

im not getting x but im getting 1/x.. Am I doing this right?

Answer 2

yes

Answer 3

\[\large \bf f(x)=\frac{4}{x}~and~g(x)=\frac{4}{x}\]
\[\large \bf f(g(x))=f(\frac{4}{x})=\frac{4}{\frac{4}{x}}=x\]

Answer 4

\[\large \bf g(f(x))=g(\frac{4}{x})=\frac{4}{\frac{4}{x}}=x\]

Answer 5

hence,proved.
@swagmaster47

Answer 6

I forgot that dividing by a fraction is the same as multiplying by the inverse! Thanks.

Answer 7

You didn't explicitly say that but you reminded me.