Use implicit differentiation to find the slope of the tangent line to the curve
-2 x^2 - 2 xy + 3 y^3 = -21
at the point ( 3,1 ).

i'm so lost here what to do, please help

Question

Use implicit differentiation to find the slope of the tangent line to the curve
-2 x^2  - 2 xy + 3 y^3 =  -21
at the point ( 3,1 ). 

i'm so lost here what to do, please help

jhannybean · Answer

@perl  cant type, im enjoying my feast >:')

fibonaccichick666 · Answer

so, if you are differentiating with respect to y, what is the derivative of just y?

fibonaccichick666 · Answer

same question, only you are differentiating with respect to x, what is the derivative of x?

perl · Answer

-2 x^2 - 2 xy + 3 y^3 = -21

use the product rule (and chain rule) on xy

and chain rule on y^3

fibonaccichick666 · Answer

@ericksol96

perl · Answer

-2x^2 - 2xy + 3y^3 = -21

the implicit derivative : 

-2*2*x - 2 ( 1*y + x* y ' ) +  3* 3* y^2 * y ' = 0

perl · Answer

any questions about that?

nincompoop · Answer

my question is why hasn't the person asking the question tried solving this himself first?

swissgirl · Answer

nin he wants some direction in life

perl · Answer

maybe technical difficulties

nincompoop · Answer

TRY solving this so we can help you help yourself.

nincompoop · Answer

HAPPY TURKEY night, Americans and US immigrants (illegal ones too)

kainui · Answer

@nincompoop can I give you two medals somehow?

nincompoop · Answer

thanks! I am stuffed, man