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Hyperbolic trig functions mabob
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So here's an example \[\int\limits \frac{dx}{1+x^2}\]
\[x=\sinh t \\ dx = \cosh t dt\]
@Jhannybean pretend there was actually a square root \[\int\limits \frac{\cosh t dt }{ \sqrt{1+\sinh^2 t}} = \int\limits \frac{\cosh t dt }{ \sqrt{\cosh^2 t}}\]
So the original one is\[\int\limits \frac{dx}{ \sqrt{1+x^2}}\]
so here's like an example where you could use hyperbolic trig sub I guess. The rest is obvious I think.
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so we can add this to our trig substitution rules
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