MEDAL!!!
Find the surface area of the regular pyramid shown to the nearest whole number. The figure is not drawn to scale/
A. 351 m^2
B. 415 m^2
C. 542 m^2
D. 790 m^2
@jim_thompson5910
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OpenStudy (jessiegonzales):
jimthompson5910 (jim_thompson5910):
what is the area of each triangular face?
OpenStudy (jessiegonzales):
117
jimthompson5910 (jim_thompson5910):
you have to cut that in half to get 117/2 = 58.5
jimthompson5910 (jim_thompson5910):
how many triangular faces are there
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OpenStudy (jessiegonzales):
6
jimthompson5910 (jim_thompson5910):
multiply 58.5 by 6 to get the lateral surface area
jimthompson5910 (jim_thompson5910):
what do you get
OpenStudy (jessiegonzales):
351
jimthompson5910 (jim_thompson5910):
so LSA = 351
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jimthompson5910 (jim_thompson5910):
now onto the base
jimthompson5910 (jim_thompson5910):
the base looks something like this
|dw:1417230433344:dw|
jimthompson5910 (jim_thompson5910):
cut it up into 6 congruent triangles
|dw:1417230471123:dw|
jimthompson5910 (jim_thompson5910):
the base of each triangle is 13 and the height of each triangle is \(\large 6.5\sqrt{3}\)
|dw:1417230524557:dw|
jimthompson5910 (jim_thompson5910):
find the area of each triangle and multiply by 6 to get the area of the base
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OpenStudy (jessiegonzales):
so 351 was just the surface area?
jimthompson5910 (jim_thompson5910):
the lateral surface area
not the whole surface area
jimthompson5910 (jim_thompson5910):
we need the base as well
OpenStudy (jessiegonzales):
oh now I see
OpenStudy (jessiegonzales):
to find the area of the base I multiply 6 by what?
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