if triangle abc is equilateral bd/bc = 1/3, CE/CA=1/3 and AF/AB=1/3. find the ratio of the area of triangle abc to the shaded area
can you post the illustration?\[\LARGE{\ddot\smile}\]
give me a minute:)
number 18.
wait
whts the answer
@sammixboo can you help with this?
@Jhannybean
It's the area of the shaded region that i can't get
me too
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\[\rm \frac{BD}{BC}=\frac{1}{3}~ , ~ \frac{CE}{CA}=\frac{1}{3}~,~\frac{AF}{AB}=\frac{1}{3}\]\[\text{Find ratio of}~~\frac{\triangle ABC}{\text{shaded region}}\]
Ok that's the question, now onto figuring it out.
@geerky42 @jim_thompson5910
@jackelyn_1234
@FibonacciChick666
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ok, I'm gonna start by labelling everything I can
so, what do we know about equilateral triangles?
it has 3 congruent sides and angles @FibonacciChick666
ok, so let's call the sides x the angles we can label too
screw that there is a thm we can use let me find it
i don't feel like deriving this
darn can't find it ok....
a piece of wire is shaped to enclose an equilateral triangle in which the area is 16squareroot of 3 cm(square). It is reshaped to enclose a rectangle whose length is 9cm. Find the area. the ans. is 27. But can someone show me the right soltion? @FibonacciChick666 @Jhannybean @shinalcantara
ok you have to have some theorem about the triangle created by the three medians in realtion to the sides, The guesser in me wants to say th ratio is 1/3 but I doubt that is right
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