Circle the first term in the trinomial. multiply it by each term in the binomial, and place each result in the spaces provided. Repeat the proccess for the second and third term of the trinomial until all of the spaces are filled in. (3x^3-2x^2+7)(x^3+2x) ___+____+____+_____+____+____
ok so remember how I said foil is a lot like the distributive property?
yes
so if it was just (3x^3-2x^2+7)(x^3) what would you do?
ohhhh
then if you just had (3x^3-2x^2+7)(2x) what would you do?
add em together and what do ya get?
whered you get (2x)
\[(3x^3-2x^2+7)(x^3+\color\red{2x})\]
I prefer to do less work so I rearranged a little
so if you have a(b+d)=ab+ad right? same idea here
i did it can you check if i am correct?
yeppers
don't skip any steps please
3x^9+6x^3-2x^5-4x^2+7x^3+14x
oh dammit
hold on ama do the work
also when you do this multiplication, what do you do with the exponents? \[x^3*x^3=?\]
add them
yea, check what you did up there before you type up your thing
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