Circle the first term in the trinomial. multiply it by each term in the binomial, and place each result in the spaces provided. Repeat the proccess for the second and third term of the trinomial until all of the spaces are filled in.
(3x^3-2x^2+7)(x^3+2x)
___+____+____+_____+____+____
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (fibonaccichick666):
ok so remember how I said foil is a lot like the distributive property?
OpenStudy (anonymous):
yes
OpenStudy (fibonaccichick666):
so if it was just (3x^3-2x^2+7)(x^3) what would you do?
OpenStudy (anonymous):
ohhhh
OpenStudy (fibonaccichick666):
then if you just had (3x^3-2x^2+7)(2x) what would you do?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (fibonaccichick666):
add em together and what do ya get?
OpenStudy (anonymous):
whered you get (2x)
OpenStudy (fibonaccichick666):
\[(3x^3-2x^2+7)(x^3+\color\red{2x})\]
OpenStudy (fibonaccichick666):
I prefer to do less work so I rearranged a little
OpenStudy (fibonaccichick666):
so if you have a(b+d)=ab+ad right? same idea here
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i did it can you check if i am correct?
OpenStudy (fibonaccichick666):
yeppers
OpenStudy (fibonaccichick666):
don't skip any steps please
OpenStudy (anonymous):
3x^9+6x^3-2x^5-4x^2+7x^3+14x
OpenStudy (anonymous):
oh dammit
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hold on ama do the work
OpenStudy (fibonaccichick666):
also when you do this multiplication, what do you do with the exponents? \[x^3*x^3=?\]
OpenStudy (anonymous):
add them
OpenStudy (fibonaccichick666):
yea, check what you did up there before you type up your thing