Question

A student has secure 40% marks to pass.He gets 40 and fails bu 40 marks.Find the max marks?

Answer 1

please solve my problem

Answer 2

he gets 40 marks but fail,right? @khorram

Answer 3

your question is difficult to read

Answer 4

is this the question
A student has secure 40% marks to pass.He gets 40 and fails bu 40 marks.Find the max marks?

Answer 5

is 2 difficult to read

Answer 6

yes its right marc

Answer 7

Hello,

"A student has to secure 40% marks to pass. He gets 40 and fails by 40 marks. Find the maximum marks?"

* Assumption: When you say fails by, I interpret that as 'got incorrect'.

\(40 + 40 = 80\)
\(40/80 = 0.5\)
\(0.5 \times 100 = 50\%\)
\(50\% > 40\%\)

So the student has passed the test, and the maximum marks possible is 80.

Answer 8

but the options are a 150 b 225 c 200 d 300 e 175

Answer 9

Hmm, did you copy the question word for word?

Answer 10

yes

Answer 11

Well I can now officially tag to the train of people who also do not understand your question. Sorry, but I cannot see to understand what your question is asking for.

Answer 12

its in university sample paper of entry test

Answer 13

the phrasing is a bit odd. is a 'mark' a correct answer

Answer 14

a mark can be right or wrong answer, (check or x mark )?

Answer 15

@perl British wise, when one says I got full marks, that means he received full points in American terms.

Answer 16

So: A student has to secure 40% points to pass. He gets 40 and fails by 40 points. Find the maximum points?

Answer 17

passing marks is 80
because student got 40 and failed by 40
so basically you have to find 80 is the 40% of which no..?
so 80/x * 100 = 40
8000/x=40
x=8000/40
x=200=maximum marks

Answer 18

I got the ans thnkx

Answer 19

he has 40 marks right now, and needs another 40 marks to pass , where passing is defined as 40% score

Let x = total number of marks

( 40 + 40 ) / x = .40

Answer 20

Ah, I see.

Answer 21

Total Marks is often termed as Maximum Marks..

Answer 22

oh , since that is the maximum points you can get on a test

Answer 23

yes.

Answer 24

here is a more challenging problem:
A candidate who gets 36% marks in an examination fails by 24 marks but another candidate who gets 43% marks gets 18 more marks than the minimum pass marks. Find the maximum marks and the percentage of pass marks.

Answer 25

40+40=80
.40n=80
n=80/.40=200
The maximum marks is 200

Answer 26

let max marks=y and pass marks=x
36% of y=x-24
43% of y=x+18
solve for x and y then pass percentage.

Answer 27

A student has to secure 40% marks to pass. He gets 40 and fails by 40 marks. Find the maximum marks?"

* Assumption: When you say fails by, I interpret that as 'got incorrect'.

40+40=80
40/80=0.5
0.5×100=50%
50%>40%

Answer 28

\[\frac{ 36 y }{ 100 }=x-24,36 y=100x-2400 ...(1)\]
\[\frac{ 43 y }{ 100 }=x+18\]
43 y=100x+1800 ...(2)
subtract (1) from (2)
43 y-36 y=100 x+1800-100x+2400
7 y=4200
y=4200/7=600
from (1)
\[43*600=100 x+1800\]
25800=100 x+1800
25800-1800=100 x
24000=100x
x=24000/100=240
pass percentage=?