Question

(sin theta + cos theta)^2 =1+ sin 2 theta?
how do i very this is an identity?

Answer 1

square and you will see it

Answer 2

this is reasonably straight forward... you need to expand a perfect square

(a + b)^2 = a^2 + 2ab + b^2

so what would your problem look like..?

Answer 3

Sin^2 + 2 cos * sin + cos ^2

Answer 4

And then?

Answer 5

great so what if I write it this way

\[\sin^2(x) + \cos^2(x) + 2\sin(x)\cos(x)\]

what do you know about

\[\sin^2(x) + \cos^(x) ~~~~and~~~~~2\sin(x)\cos(x)\]

Answer 6

oops

\[\sin^2(x) + \cos^2(x)\]

Answer 7

Saw it thanks !!!