4x^2+kx+25=0 Find Values of k that ensure that the given equation has exactly one solution
Anyone get this?
4x^2+kx+25=0 is in the form ax^2+bx+c=0 where a = 4, b = k, c = 25
"Find Values of k that ensure that the given equation has exactly one solution" so this means the discriminant D is equal to 0 The discriminant formula is D = b^2 - 4ac
plug in a = 4, b = k, c = 25 and D = 0 then solve for k
K+/- 20
so if there wasn't one solution? you can use quadratic formula?
yes k = 20 or k = -20 will make 4x^2+kx+25=0 have exactly one solution for x
if you want 4x^2+kx+25=0 to have exactly 2 solutions, then you would look for values of k that make D > 0 true if you want 4x^2+kx+25=0 to have no real solutions, then you would look for values of k that make D < 0 true
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