Question

Another one: Moivre theorem: (sqrt2cis(pi/9)^6... now what am I doing wrong?

Answer 1

\[\sqrt{2}(\cos(\frac{ \pi }{9})n+isin(\frac{ \pi }{ 9 }))^{6} = 6(\cos \frac{ 2\pi }{ 3 }+isin \frac{ 2\pi }{3 })\]

Answer 2

six square roots of 2 should give us 2x2x2, yes?
Check your multiplication there :)

Answer 3

6(-1/2 + sqrt3 /2 i) = -3+3sqrt3i

Answer 4

oooo so i put 6 instead of 8

Answer 5

ya that's the only mistake i see :D

Answer 6

omgosh my mistakes are soooo dumb... thank u

Answer 7

hehe :3

Answer 8

thanks!