Question

in how many different ways can seven elements be selected in order from a set with three elements when repetition is allowed?

Answer 1

Since it needs to be in order, would it be a combination or permutation?

Answer 2

its a permuation

Answer 3

Yep. And how many things are we going to be choosing?

Answer 4

3

Answer 5

Well, it's a little confusing how it's written. It's actually 7 things that we're choosing.

Answer 6

ok

Answer 7

So we'll need 7 blanks.

- - - - - - -

Answer 8

How many options do we have when we're selecting the first one?

Answer 9

7 then 6 then 5 then 4 then 3 then 2 and lastly 1

Answer 10

Not quite - this one's a little different.

Answer 11

It says we're choosing from a set with 3 elements. So that means we have 3 choices for the first position.

Answer 12

And then notice they tell us that repetition is allowed?

Answer 13

then two and one for the last

Answer 14

Well, we can repeat. That means we still have 3 choices for the 2nd one!

Answer 15

ok

Answer 16

and again 3 for the next one...and 3 choices for all 7.

Answer 17

3 * 3 * 3 * 3 * 3 * 3 * 3 = ?

Answer 18

2187

Answer 19

Yep. 3 * 3 * 3 * 3 * 3 * 3 * 3 = 2187

Answer 20

Mira you awesome thanks

Answer 21

Hehe. Yw :^)

Answer 22

i may have some more later if your on
I have a hard time with some of theses

Answer 23

You can ask me for help anytime, I'll be here.

Answer 24

cool thanks the only thing i really understand with descrete math is the vertices and lines