Question

In a statistics class there are 18 Juniors and 10 Seniors; 6 of the seniors are female, 12 of the juniors are male. If a student is selected at random, find the probablity of selecting
a) a junior or a female
b) a senior or a female
c)not a junior male

Answer 1

a) P(junior) +P(female)
b) P(senior) + P(female)
c). 1 - P(male)

Answer 2

So.. a) 18+6?

Answer 3

Total students = senior + junior
P(junior) = junior/total students

Answer 4

P(A junior or a female) = (18/28) + (12/28)-(6/28) = 24/28 = 6/7
P(A senior of a female) = (10/28) + (12/28) –(6/28) = 16/28= 4/7
P(A junior or a senior) = (18/28) + (10/28) = 28/28 = 1