Question

What is the range of f(x)=(x+4)^2+7?
1 y>or equal to -4
2 y>or equal to 4
3 y=7
4 y>or equal to 7

Answer 1

\[(x+4)^2\geq 0\] because it is a square
that makes
\[(x+4)^2+7\geq 7\]

Answer 2

the vertex is (-4,7) and the parabola is positive so there the vertex must be the minimum. so the range is the y>=7