Question

i need help factoring x^3-3x^2+6x-18
i need help with the steps asap

Answer 1

You have to cut the problem in half so it would be
(x^3-3x^2)+(6x-18)
then find the common denominator in each so it would then be
x^2(x-3)+6 (x-3)
and then put it together( the outside terms together)
(x^2+6)+(x-3)^2

Answer 2

thank you so much is it okay if i ask you another question?

Answer 3

of course, go ahead

Answer 4

4/5-radical 13

Answer 5

sqrt = square root

4 / (5 - sqrt(13) )

multiply top and bottom of fraction by conjugate of denominator:
4(5+sqrt(13)) / ( (5-sqrt(13))(5+sqrt(13) )

multiply out denominator:
4(5+sqrt(13)) / (25-13)
4(5+sqrt(13)) / 12

simplify denominator by factoring out 4:
(5+sqrt(13) / 3

ANSWER: (5+sqrt(13) / 3

Answer 6

honestly thank you so much no one has been able to help me

Answer 7

you're welcome!!