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if we know that y varies inversely as x and y=8 when x=15, what is y when x=10 what is the constant of variation
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i think i remember how this works start with \[y=kx\] then put \(y=8,x=15\) and get \[8=k\times 15\]
solve for \(k\) giving \[k=\frac{8}{15}\] so the variation is \[y=\frac{8}{15}x\]
finally put \(x=10\) and compute \[y=\frac{8}{15}\times 10\]
its going to be y= (8/10)x {{Same as what the other person said}}
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