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Mathematics 28 Online
OpenStudy (anonymous):

if we know that y varies inversely as x and y=8 when x=15, what is y when x=10 what is the constant of variation

OpenStudy (anonymous):

i think i remember how this works start with \[y=kx\] then put \(y=8,x=15\) and get \[8=k\times 15\]

OpenStudy (anonymous):

solve for \(k\) giving \[k=\frac{8}{15}\] so the variation is \[y=\frac{8}{15}x\]

OpenStudy (anonymous):

finally put \(x=10\) and compute \[y=\frac{8}{15}\times 10\]

OpenStudy (anonymous):

its going to be y= (8/10)x {{Same as what the other person said}}

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