Convert the given coordinates to the indicated ordered pair: (1, - sqrt 3) to (r, theta). I have found r to be 2 but I am having trouble finding theta. Please help!!!
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OpenStudy (freckles):
|dw:1417404702409:dw|
so just do arctan(y/x) foe theta
OpenStudy (anonymous):
Okay, thank you so much (again). Also, did I get r correct?
OpenStudy (anonymous):
Also, when I do arctan(y/x) I get -1.047... should I have a more accurate answer in terms of pi for theta?
OpenStudy (anonymous):
Okay! I think I've found the answer.... the converted pair would be \[(2, -\pi/3)\] ?
OpenStudy (freckles):
sorry notifications isn't working properly
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OpenStudy (freckles):
r^2=1+3=4
r=2
so good
and yes theta=-pi/3
now if there is no restriction on r or theta
then you are done
OpenStudy (anonymous):
Well actually, is there any restriction since it must be in the fourth quadrant?
OpenStudy (freckles):
your r and theta is fine
OpenStudy (freckles):
Sometimes the teacher wants a positive theta
OpenStudy (freckles):
or a negative r
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OpenStudy (freckles):
but if there is nothing like that given then you are done
OpenStudy (anonymous):
yeah, it just says to convert. Thank you so much!!