Convert the given coordinates to the indicated ordered pair: (1, - sqrt 3) to (r, theta). I have found r to be 2 but I am having trouble finding theta. Please help!!!
|dw:1417404702409:dw| so just do arctan(y/x) foe theta
Okay, thank you so much (again). Also, did I get r correct?
Also, when I do arctan(y/x) I get -1.047... should I have a more accurate answer in terms of pi for theta?
Okay! I think I've found the answer.... the converted pair would be \[(2, -\pi/3)\] ?
sorry notifications isn't working properly
r^2=1+3=4 r=2 so good and yes theta=-pi/3 now if there is no restriction on r or theta then you are done
Well actually, is there any restriction since it must be in the fourth quadrant?
your r and theta is fine
Sometimes the teacher wants a positive theta
or a negative r
but if there is nothing like that given then you are done
yeah, it just says to convert. Thank you so much!!
np
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