Question

I'm not sure if there's a better or more elegant way to do this, but I'm dealing with a Stokes' Theorem problem where the 2D area integrated over is a square centered on the origin.

Answer 1

Posted here is the information on the problem: http://i.imgur.com/IGHPx4u.png

Answer 2

@ganeshie8 , what I'm confused about is that I can already see that setting up the integral will be rather messy, won't it?

Answer 3

OH, nevermind, I was thinking about it as a line integral for some reason. Let me take a shot at it now.