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Algebra
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(5x-4)^2=36
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x=2
(5x-4)^2=36 5x^2-(4*4)=36 5x^2-16=36 +16 +16 5x^2=36+16 5x^2=42 (and then from there idk if you devide on both sides by five, I never learned that yet and then if you're suppose to... x^2=8.4, and then multiply itself and get 70.56)
was my answer correct? >.<
well, plug it back in. Replace x with 2
i did and it was right
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\[(5x-4)^2=36\]square root both sides \[=\sqrt{(5x-4)^2}=\pm \sqrt{36}\]\[=5x-4 = \pm \sqrt{36}\]\[=5x-4=+6\]\[=5x-4=-6\]
(5x-4)^2=36 5x-4 = 6 OR 5x -4 = -6 Solve each equation and check. Expect two answers.
Now solve both of these functions for x.\[5x-4=6\]\[5x-4=-6\]
@jokay2015 What did you get for the two answers?
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