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Geometry 6 Online
OpenStudy (sagewilson):

Before I give you guys the question. How do you do the 45-45-90 theorem because that is confusing me. http://i.imgur.com/YmAEe1F.png I would like some explaining on what to do please.

Directrix (directrix):

I attached a diagram of the theorem. If you have a 45-45-90 theorem, the hypotenuse is square root 2 times the leg length. If you have the hypotenuse length on the same type triangle and need the leg length, then divide the hypotenuse by square root of 2.

OpenStudy (sagewilson):

I still don't quite understand how to do the problem

Directrix (directrix):

If the hypotenuse is 5 times square root 6, then divide by square root 2. |dw:1417434252069:dw|

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