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How do you find the square root of 121? Medal for fast help! :)
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Answer: 11
thanks, any way you could summarize how to figure that out?
first find all odd or even prime factors for given no. then on applying square root we get the required value
what does applying square root mean?
1, 11 and 121 are the prime factors of 121
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Just now that 10 * 11 is 110 so if you add 11 more you get 121 so therefore you now that the answer is 11 * 11
okay so basically square root is what number times itself can equal the given number?
the square root of 121 is 11 and -11 \(b\) is the square root of a number \(a\) if \(b^2=a\) since \(11^2=121\) and \((-11)^2=121\) both 11 and -11 are square roots of 121
Okay :) Thanks!
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