Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Cos(Arctan 5)

OpenStudy (cwrw238):

first find the angle whose tangent is 5 (that's the arctan 5) then take the cosine of the result

OpenStudy (anonymous):

Yes, I understand the process, however, I'm having trouble finding the angle whose tangent is 5

OpenStudy (cwrw238):

the arctan might be tan-1 on your calculator

OpenStudy (anonymous):

We aren't allowed to use a calc on this problem.

OpenStudy (cwrw238):

oh OK then draw the right angled triangle |dw:1417459453917:dw|

OpenStudy (cwrw238):

the angle whose tangent is 5 is angle x work out the hypotenuse usin pythagoras then cos x = 1 / hypotenuse

OpenStudy (anonymous):

Ah yes! I had that in mind but was unsure if that would be correct! using A^2 + B^2 = c^2 1 + 25 = c^2 c= sqrt26 Cosx = 1/ sqrt26 ?

OpenStudy (cwrw238):

as i expect you knoe tan = opposite /adjacent and c os = adjacent /hypotenuse

OpenStudy (cwrw238):

yes thats right

OpenStudy (anonymous):

Awesome! Thank you so much!

OpenStudy (cwrw238):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!