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Mathematics
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Cos(Arctan 5)
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first find the angle whose tangent is 5 (that's the arctan 5) then take the cosine of the result
Yes, I understand the process, however, I'm having trouble finding the angle whose tangent is 5
the arctan might be tan-1 on your calculator
We aren't allowed to use a calc on this problem.
oh OK then draw the right angled triangle |dw:1417459453917:dw|
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the angle whose tangent is 5 is angle x work out the hypotenuse usin pythagoras then cos x = 1 / hypotenuse
Ah yes! I had that in mind but was unsure if that would be correct! using A^2 + B^2 = c^2 1 + 25 = c^2 c= sqrt26 Cosx = 1/ sqrt26 ?
as i expect you knoe tan = opposite /adjacent and c os = adjacent /hypotenuse
yes thats right
Awesome! Thank you so much!
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yw
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