Alright, another surface integral question, working so far posted below:

Question

mendicant_bias · Answer

mendicant_bias · Answer

(Stopped computing the magnitude of the cross product when it started looking really ugly; am I doing this right?)

mendicant_bias · Answer

@wio  (lol sorry), looking over it now.

mendicant_bias · Answer

Should I have done a transform or something or selected a different u,v? Maybe polar?

anonymous · Answer

@party_girl

mendicant_bias · Answer

mendicant_bias · Answer

mendicant_bias · Answer

Alright, did some more, think I got the right integrand/magnitude of cross product result

mendicant_bias · Answer

anonymous · Answer

You decided you didn't want to deal with cylindrical coords anymore?

mendicant_bias · Answer

Wait, what, oh, I changed back. Yeah, the earlier stuff was a mistake, all the recent stuff is in "cylindrical"/polar.

mendicant_bias · Answer

Yup, the integrand is correct, hooray.

anonymous · Answer

I'm getting $\sqrt 5 r$ for my magnitude.

mendicant_bias · Answer

Yup, last post, unless I linked incorrectly.

mendicant_bias · Answer

(Some of my posts might be lagging and not showing up)

mendicant_bias · Answer

anonymous · Answer

Why @party_girl ?