A Line has a slope of -2/3 and passes throug the points (-3, 8). what is the equation of the line? @AriPotta

Question

aripotta · Answer

so the way to go with this is to plug your info into point-slope form$$y - y _{1}=m(x-x _{1})$$

anonymous · Answer

ok so what would be the y, the m and the x?

aripotta · Answer

you have a point (-3,8). a point is in the form (x,y) so -3 will be your x1 and 8 will your y1. the y and x stay the same and the m is your slope, -2/3

aripotta · Answer

y - 8 = -2/3(x + 3)

aripotta · Answer

does that make sense?

anonymous · Answer

yea that makes sense but the answers choices are different on mine

aripotta · Answer

can you post the choices?

aripotta · Answer

they probably want you to write it in a different form

anonymous · Answer

y=-2/3x+6
y=-2/3x+8
y=6x-2/3
y=8x-2/3

aripotta · Answer

yea, so those choices are in slope-intercept form. we can easily convert our equation into slope-intercept

anonymous · Answer

ok, how do we do that?

aripotta · Answer

y - 8 = -2/3(x + 3)

ok. so first distribute the -2/3

anonymous · Answer

how do i distribute them? by dividing?

aripotta · Answer

multiplying. so -2/3 times x = -2/3x. -2/3 times 3 = -2

y - 8 = -2/3x - 2

aripotta · Answer

then, to get y by itself, you need to add 8 to both sides

anonymous · Answer

y=-2/3x+6?

aripotta · Answer

yep

anonymous · Answer

ok thanks!

aripotta · Answer

no problemo :)