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divide by 5 and move everything to one side x^2 + 6x + 13 = 0
\(\large\color{black}{5x^2 = -30x - 65 }\) add 30x and then 65 to both sides \(\large\color{black}{5x^2 + 30x + 65=0 }\) divide each term in equation by 5. \(\large\color{black}{x^2 + 6x + 13=0 }\)
divide everything by 5
and then you'll have to use the quadratic equation to solve for x
you can't factor it, so I would complete the square. subtract 4 from both sides.
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all your answers are imaginary.
That works too
\(\large\color{black}{x^2 + 6x + 13=0 }\) \(\large\color{black}{x^2 + 6x + 13-4=0-4 }\) \(\large\color{black}{x^2 + 6x + 9=-4 }\)
go on...
what is the square root of -4? have you learned about imaginary numbers (such as i) ?
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