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Mathematics 11 Online
OpenStudy (anonymous):

I NEED HELP!!!!!

OpenStudy (anonymous):

OpenStudy (michele_laino):

please you have to maximaze the function p(x), in other words you have to calculate the derivative of p(x) and the solve the equation: \[\frac{ dp }{ dx }=0\]

OpenStudy (michele_laino):

please, write the derivative of p(x), namely dp/dx

OpenStudy (michele_laino):

@omgitsjc

OpenStudy (michele_laino):

\[\frac{ dp }{ dx }=-20x+200\] is it right?

OpenStudy (michele_laino):

@omgitsjc Please, note that I can not say you the answer directly, since the code of conduct. Nevertheless I can help you in your reasoning!

OpenStudy (anonymous):

Sorry, The cable guy came and i walk off.

OpenStudy (anonymous):

and @Michele_Laino i dont know.

OpenStudy (michele_laino):

now, please set -20x+200=0, and find x, write your answer, please!

OpenStudy (anonymous):

ok.. HOw do i find x.. Is it 10?

OpenStudy (michele_laino):

that's right!

OpenStudy (michele_laino):

now insert x=10, into the function p(x), then calculate it, and write what you get, please!

OpenStudy (michele_laino):

namely calculate p(10) @omgitsjc

OpenStudy (anonymous):

oh... Ok, just dumb it down a bit.

OpenStudy (anonymous):

so do i do -20*10+200=0?

OpenStudy (michele_laino):

noo, please you have to do this: \[-10*(10)^{2}+200*10-250=-10*100+2000-250=...\]

OpenStudy (michele_laino):

so, please, what do you got?

OpenStudy (anonymous):

ok that first one was 2750 and the second half was 850

OpenStudy (anonymous):

I get the felling i needed or need to do something more

OpenStudy (michele_laino):

from preceeding calculus the result is 750, are you agree?

OpenStudy (anonymous):

yes, i think so

OpenStudy (michele_laino):

ok! then x=10 and p(x)=750 is your answer, namely the third option

OpenStudy (michele_laino):

that's all

OpenStudy (anonymous):

wow! Thx, and sorry for walking away before.

OpenStudy (michele_laino):

don't worry, thank you!

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