Find the derivative of the function using the definition of derivative. the square root of 8-x
oh the dreaded limit definition of derivatives
haha can i just teach you the shortcut lol
yes
no that wont help you on a test
I know that you pull down the number that is above the exponent so the x would disappear and become 1 but would the 8 also disappear?
so you have \[\lim_{h \rightarrow 0} \frac{f(x+h) - f(x)}{h} = \lim_{h \rightarrow 0} \frac{\sqrt{8-(x+h)} - \sqrt{8-x}}{h}\]
ahh yes the 8 would disappear .... derivative of constant is 0
so it would just be the square root of 1?
no because the whole thing is inside of sqare root, its a bit more complicated
Now im confused
anyway are you talking about limit definition here?
or where are you in your calculus course? this way i know the correct approach to help you
I am on chapter 2.8
whats the chapter heading ...
Nevermind i figured it out. Thank you
alrighty then
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