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Will give fan and medal!!! Write x^2 - 2x - 3 = 0 in the form (x - a)^2 = b, where a and b are integers.
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(x - 4)^2 = 3 (x - 3)^2 = 2 (x - 2)^2 = 1 (x - 1)^2 = 4
What do you think the answer is?
(x - 3)^2 = 2 or (x - 1)^2 = 4 @tom982
It's neither of those. For an quadratic x^2+bx+c, to write it in completed square format we say it's (x+0.5b)^2+c-0.5b^2. In your equation, b=-2 and c=-3, sub these numbers in for your answer.
(x+0.5(-2))^2+(-3)-0.5(-2)^2 like this?
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Exactly like that :)
so now solve it, right?
Would it be (x - 4)^2 = 3 by any chance?
@tom982
@ganeshie8 @jim_thompson5910
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@tom982
How have you gone from (x+0.5(-2))^2 to (x-4)^2?
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