x^2/x+100=50
It is, \(\Large\color{blue}{ \frac{x^2}{x+100} =50 }\) right?
Yes
multiply both sides times "x+100"
what do you get ?
Let's solve your equation step-by-step. x2 x +100=50 Multiply all terms by x and cancel: x2+100x=50x x2+100x−50x=50x−50x(Subtract 50x from both sides) x2+50x=0 x(x+50)=0(Factor left side of equation) x=0 or x+50=0(Set factors equal to 0) x=0 or x=−50 Check answers. (Plug them in to make sure they work.) x=0(Doesn't work in original equation) x=−50(Works in original equation) Answer: x=−50
Solomon for the fraction side you multiply x+100/1?
x^2+100x−50x=50x−50x(Subtract 50x from both sides)
yes, you mutliply times x+100, that will cancel the x+100 on the bottom, and give you just x^2 on the left. On the right side though, when you multiply 50 times (x+100) what do you get?
50x+5000
To clear up the fraction side any time you multiply the denominator you just end with the numerator?
yes.
AND now we have \(\large\color{black}{ x^2=50x+5000 }\)
now x^2-50x-5000 and factor
yes, exactly.
but, \(\large\color{black}{ x^2-50x-5000=0 }\) (right?)
don't forget the "=0" part.
yes , factor it.
(x-100)(x+50)
yes.
so 100 and -50
there you go!
this is correct. (if you want, you can check them)
Thanks, mine if I give you another problem? I'm stuck on that too..
I am going offline soon, so I don;t know.
It's the first question on the open section, try it if you can spare a few minutes
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