PLEASE HELP ME
Solve, using the substitution method.
j + k = 3
j – k = 7
The solution is (8, 1)
The solution is (5, –2)
There is no solution.
There are an infinite number of solutions.
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OpenStudy (anonymous):
B. The solution is (5, 2)
jimthompson5910 (jim_thompson5910):
solve j – k = 7 for j
j – k = 7
j – k+k = 7+k
j = 7+k
jimthompson5910 (jim_thompson5910):
then plug j = 7+k into the first equation j + k = 3
j + k = 3
7+k + k = 3 ... notice how i replaced j with 7+k
solve for k
OpenStudy (anonymous):
checking my answers
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OpenStudy (anonymous):
@Haichi that's not exactly helping things. Jim was doing a great job explaining and you waltz in with an unnecessary comment.
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OpenStudy (anonymous):
@tom982 thank you
OpenStudy (anonymous):
come on now, lets not get in a fight at 11pm
OpenStudy (haichi):
ok soz
OpenStudy (haichi):
Jeez
OpenStudy (anonymous):
im sorry i should have never addded on to it can we please continue
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OpenStudy (anonymous):
@jim_thompson5910
OpenStudy (haichi):
not rlly
TheSmartOne (thesmartone):
\(\color{blue}{\text{Originally Posted by}}\) @Haichi
figure them out ur smart enough
\(\color{blue}{\text{End of Quote}}\)
Says the person who didn't help...