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Mathematics 15 Online
OpenStudy (brucebaner):

What is the equation of the line?

OpenStudy (brucebaner):

A y= -2x B Y=- 1/2x C y=1/2x D y=2x

OpenStudy (brucebaner):

@sammixboo

OpenStudy (ageta):

which line

OpenStudy (brucebaner):

help me @sammixboo and @ageta

OpenStudy (brucebaner):

@rosho

OpenStudy (brucebaner):

@GoldPhenoix

OpenStudy (brucebaner):

@rizwan_uet

OpenStudy (brucebaner):

help me @rizwan_uet

OpenStudy (anonymous):

can you find the slope of this line???

OpenStudy (brucebaner):

no

OpenStudy (anonymous):

ok lets find the slope of this line. slope = m = (y2-y1 )/ (x2-x1) take any two points on this line say (x1,y1= )(1,2) and (x2,y2)=(2,4) substituting these values in the above formula we get slope = m = (4-2)/(2-1) can you find the slope now???

OpenStudy (brucebaner):

sorry im not what good at slope

OpenStudy (anonymous):

ok so the slope is = m = 2 now we have slope intercept form of line which is y = mx + b where m = slope and b = y-intercept here m = 2 and b = 0 thus putting in formula we get y = 2x + 0 => y = 2x

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