Question

Help!

prove 1+sec^2 x/tanx = 1+cos^2 x/sinxcosx

Answer 1

Is this your equation?\[1+\frac{sec^2 x}{tanx} = 1+\frac{cos^2x}{sinxcosx}\]

Answer 2

need help

Answer 3

Or perhaps this?\[ \frac{1+sec^2 x}{tanx} = \frac{1+cos^2x}{sinxcosx} \]

Answer 4

the second one

Answer 5

Okay let's work on the left side:
\[ LHS = \frac{1+sec^2(x)}{tan{x}} \]
\[ \frac{1+\frac{1}{cos^2(x)}}{\frac{sinx}{cosx}} \]
\[ (1+\frac{1}{cos^2(x)})*{\frac{cosx}{sinx}} \]
\[ \frac{cosx+\frac{1}{cosx}}{sinx} \]
\[ \frac{cosx+\frac{1}{cosx}}{sinx} * \frac{cosx}{cosx} = \frac{1+cos^2x}{sinxcosx} = RHS \]

Answer 6

this makes so much sense now thank you so much!!