What is the quadratic function that is created with roots -10 and -6 and a vertex at (-8, -8)?

using the equation f(x) = ax^2 + bx + c

Question

What is the quadratic function that is created with roots -10 and -6 and a vertex at (-8, -8)?

using the equation f(x) = ax^2 + bx + c

anonymous · Answer

@SolomonZelman @Nurali @campbell_st

campbell_st · Answer

ok... so x = -10 is a root then  (x + 10) is a factor  and x = - 6 is a root (x + 6) is a factor

the equation is 

y = a(x + 10)(x+6) 

use the point (-8, -8) to find the value of a  by substituting x = -8 and y = -8

then you can distribute for the equation

anonymous · Answer

thank you

anonymous · Answer

so itd be 
-8 = a(-8 + 10) (-8 + 6)

and then a=2

is that right?

anonymous · Answer

@campbell_st

campbell_st · Answer

thats correct

now substitute it back

y = 2(x+10)(x+6)  and distribute

anonymous · Answer

wait, why do i need to do that?

tkhunny · Answer

Why did you post this question twice?  This is also spamming, according to OpenStudy.  If you had a question for these volunteers, you should have voiced it here, rather than reposting.