x = 1 + 2y^2

Question

x = 1 + 2y^2

adamaero · Answer

for the equation 
(2pi)integral(?*sqrt(1+(derivative))
? = y
or ? = x 
when rotating about the x-axis?

adamaero · Answer

at first I did
$$\sqrt{\frac{ x-1 }{ 2 }} = y$$
because I thought that would be the "?" 
Am I wrong, is that actually for rotating about the y-axis?

anonymous · Answer

What are you supposed to do?

adamaero · Answer

find the surface area by rotating the curve about the x-axis

anonymous · Answer

$$
x=1+2y^2
$$Is only one of the boundaries.  What are the other boundaries?

anonymous · Answer

I assume $y=0$ is a boundary as well.

adamaero · Answer

I know how to solve, I am just asking what I put in for "?"

adamaero · Answer

you do not need the bounds for MY question

adamaero · Answer

I am not asking for you to solve anything

anonymous · Answer

If there is no upper boundary for x, then the answer is infinity.

anonymous · Answer

You just want an anti derivative?

adamaero · Answer

like I said, there is bounds but it is irrelevant to my question
no! wio I don't think you know what I'm asking or how to set up this problem

anonymous · Answer

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anonymous · Answer

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