Which graph represents the function of f(x) = the quantity of 9 x squared plus 9 x minus 18, all over 3 x plus 6?
plz help me @myininaya
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myininaya (myininaya):
\[f(x)=\frac{9x^2+9x-18}{3x+6}\]
is what you mean?
OpenStudy (anonymous):
correct :)
myininaya (myininaya):
I suggest factoring everything
myininaya (myininaya):
the top and the bottom
myininaya (myininaya):
3x+6= what in factored form?
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OpenStudy (anonymous):
idk how to do that sorry :/
myininaya (myininaya):
3x and 6 have what as a common factor?
OpenStudy (anonymous):
wat do u mean?
myininaya (myininaya):
if we write the factors of both 3x and 6
we see that 3x=3*x
and 6=3*2
so 3x has factors 3 and x
and 6 has factors 3 and 2
therefore the only factor tht 3x and 6 have in common is 3
therefore we can factor 3x+6
by factoring out 3
so 3x+6=3(x+2)
myininaya (myininaya):
I guess since you have never done that you will not be able to tell how to factor the numerator
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OpenStudy (anonymous):
ok
myininaya (myininaya):
like you don't know how to factor
\[9x^2+9x-18?\]
OpenStudy (anonymous):
i think i do
myininaya (myininaya):
oh okay
let's see if you can factor that
OpenStudy (anonymous):
i'm stuck.. :/
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myininaya (myininaya):
first did you factor out what all three terms had in common?
myininaya (myininaya):
9x^2=9*x^2
9x=9*x
-18=9*(-2)
myininaya (myininaya):
so you can write
\[9x^2+9x-18 \text{ as } 9(x^2+x-2)\]
myininaya (myininaya):
can you factor the x^2+x-2?
myininaya (myininaya):
what are two integer numbers that multiply to be -2 and add up to be 1?
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OpenStudy (anonymous):
2 and -1
myininaya (myininaya):
so the factors are (x+2) and (x-1)
myininaya (myininaya):
so 9x^2+9x-18
is 9(x+2)(x-1)
OpenStudy (anonymous):
i always have trouble figuring out the numbers next to x while factoring
myininaya (myininaya):
\[f(x)=\frac{9(x+2)(x-1)}{3(x+2)}\]
so we have a discontinuity at what x value?
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myininaya (myininaya):
we cannot divide by 0
myininaya (myininaya):
so x+2 cannot be 0
but x+2=0 when x=?
OpenStudy (anonymous):
-2
myininaya (myininaya):
\[f(x)=\frac{9(x+2)(x-1)}{3(x+2)}=3(x-1), x \neq -2 \]
myininaya (myininaya):
our function will not exist at x=-2
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myininaya (myininaya):
the x+2's canceled
myininaya (myininaya):
and 9/3=3
myininaya (myininaya):
do you think you can graph f(x)=3x-3 when x doesn't equal 2
OpenStudy (anonymous):
so in a graph its supposed to look like this? |dw:1417565475249:dw|