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PLEASE HELP ME
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you got this on speed dial?
do you know how to calculuate the slope using that
@satellite73 i hope im not breaking a rule
no no i am just busting them for you for posting so much no problem at all
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you want the answer or the method?
method please
we can do both first the answer: \[y=-\frac{4}{3}x+6\] now method
slope of the line through \((6,-2),(-12,22)\) is computed via \[\frac{22-(-2)}{-12-6}=\frac{24}{-18}=-\frac{4}{3}\]
the the all mighty point slope formula \[y-y_1=m(x-x_1)\] gives you \[y+2=-\frac{4}{3}(x-6)\]
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ok
solve for \(y\) by disttributing first \[y+2=-\frac{4}{3}x+8\] then subtract \(2\) \[y=-\frac{4}{3}x+6\]
all steps are there, so try the next one and see if you can do it
ok thanks
yw
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