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Mathematics 24 Online
OpenStudy (anonymous):

PLEASE HELP ME

OpenStudy (anonymous):

OpenStudy (anonymous):

First subtract 8 from each side. Second divide the 56 by 8

OpenStudy (anonymous):

64-8=56 56/8=7

OpenStudy (anonymous):

You are trying to get x "alone"

OpenStudy (anonymous):

B

OpenStudy (ahsome):

\[8x+8\ge64\] Just pretend the \(\le\) is the same as an equal sign, and keep going: \[8x+8\ge64\]\[8x\ge56\]\[x\ge\frac{56}{8}\]\[x\ge7\]. So it would be the second option

OpenStudy (ahsome):

For the second line, it was meant to be \(\ge\)

OpenStudy (anonymous):

And yes it is B :)

OpenStudy (anonymous):

thanks everyone this is hard who should I give the medal too

OpenStudy (anonymous):

@Ahsome

OpenStudy (anonymous):

@Ahsome explained it better

OpenStudy (ahsome):

I think I already have enough, @LiamR ;)

OpenStudy (anonymous):

You can never have to many XD @Ahsome and you honestly did a better job explaining it.

OpenStudy (anonymous):

to all three of you

OpenStudy (anonymous):

Thanks @welligya...

OpenStudy (anonymous):

welcome but you did something way better so no need to thank me

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