-x-y=1
im going graphing
when you convert it into slope-intercept form (y = mx + b), graphing should be easy
i dont understand it at all im bad at math
you wanna take your original equation, -x - y = 1, and get y by itself on the left hand side. do you know how to do that?
well you gotta do they whole x and y table .. but to your ? no i don't lol im dumb
i don't think you need to do an x/y table. you're graphing it on a coordinate plane, right?
i think so idk... but either way i don't know what im doing
lol ok. so what i was saying earlier...-x - y = 1, to get y by itself, first add x to both sides since + is the opposite of - so -y = x + 1 and we don't want y to be negative, so to fix that, we're going to multiply the whole equation by -1 so y = -x - 1
then what do i do
so the y-intercept is -1. that's gonna be our first point on the graph, (0,-1) the slope is -1. so that means, from our first point (0,-1), we'll go down 1 and over to the right 1. that'll give us our second point (1, -2). and because we have two points, we can put our line between them
did that make sense?
but i need three points, and how did you get the points
why do you need three points?
idk thats just what it is
ok so then just use your equation y = -x - 1, substitute 0, 1, and 2 for x and solve for y to get your three points
i have to go
sorry i can't help more
but wait i don't know how
i'll do 0 for you y = -x - 1 y = -0 - 1 y = -1 which gives us a point of (0,-1)
but how do you solve to get (0,-1)
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