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Mathematics
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Mean Value Theorem http://puu.sh/df03Q/9880984a6b.png
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first if the criteria is met for M.V.T on the interval [a,b] then you can find c by doing: \[f'(c)=\frac{f(b)-f(a)}{b-a}\]
so i take the derivative and set = to 50
24^2 +8 = 50?
just to be sure how did you get 50?
also where does that derivative come from?
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24^2+8?
oh 24x^2+8 is what you meant
oh typo 24x^2 + 8
but I'm not sure that 50 is the slope of the secant line
\[24c^2+8=\frac{f(2)-f(0)}{2-0}\]
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you did that right?
for the right hand side?
oh and the number should be 48 instead of 50, bad math :P
im going to use my calculator because I can't trust myself with arithmetic sometimes
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should be 40
so solve 24c^2+8=40
i got (2sqrt3)/3
sounds good
thank you
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np
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