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Mathematics 18 Online
OpenStudy (anonymous):

Mean Value Theorem http://puu.sh/df03Q/9880984a6b.png

OpenStudy (freckles):

first if the criteria is met for M.V.T on the interval [a,b] then you can find c by doing: \[f'(c)=\frac{f(b)-f(a)}{b-a}\]

OpenStudy (anonymous):

so i take the derivative and set = to 50

OpenStudy (anonymous):

24^2 +8 = 50?

OpenStudy (freckles):

just to be sure how did you get 50?

OpenStudy (freckles):

also where does that derivative come from?

OpenStudy (freckles):

24^2+8?

OpenStudy (freckles):

oh 24x^2+8 is what you meant

OpenStudy (anonymous):

oh typo 24x^2 + 8

OpenStudy (freckles):

but I'm not sure that 50 is the slope of the secant line

OpenStudy (freckles):

\[24c^2+8=\frac{f(2)-f(0)}{2-0}\]

OpenStudy (freckles):

you did that right?

OpenStudy (freckles):

for the right hand side?

OpenStudy (anonymous):

oh and the number should be 48 instead of 50, bad math :P

OpenStudy (freckles):

im going to use my calculator because I can't trust myself with arithmetic sometimes

OpenStudy (freckles):

should be 40

OpenStudy (freckles):

so solve 24c^2+8=40

OpenStudy (anonymous):

i got (2sqrt3)/3

OpenStudy (freckles):

sounds good

OpenStudy (anonymous):

thank you

OpenStudy (freckles):

np

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