Question

alright dudes i got problem with equation of a line functions
i am up to solving for b (y=mx+b)
points are (-3.5) and (2,8)
y=3/5x+b
now i am stuck on solving this part
5=3/5*(-3) +b and 8= 3/5*(2) + b

answer is suppose to be 34/5=b not sure how to get there

Answer 1

y = (3/5) x + b

b is the y-intercept which is where the graph cuts the y-axis.

To get on the y-axis, the x coordinate of the y intercept has to be zero.

Think of the y-intercept as being in the form ( 0, b).

You were given two points at the beginning.

They are points on the line.

So, they have to make the equation true.



.

Answer 2

I chose point (2, 8) where x = 2 and y = 8

y = (3/5) x + b

8 = (3/5) * 2 + b

Solve this for b and you'll have the y-intercept.

Then, place it in this equation for b: y = (3/5) x + b

@Kittens4Mittens

Answer 3

Now, another way to do this using technology.

Go to the online equation of a line calculator site at:

http://www.webmath.com/equline1.html

You'll see something like that pictured on the attachment.

Place the point coordinates into the calculator slots.

Click on the find the equation tab.

A discussion of how to do the problem follows along with the equation in y = mx + b form.

Answer 4

thank you man!

Answer 5

You are welcome.