Question

Find the non-extraneous solutions of...

Answer 1

\[\sqrt{x+9}-5=x+4\]

Answer 2

@perl

Answer 3

@Jhannybean

Answer 4

@Secret-Ninja

Answer 5

@Abhisar

Answer 6

Well for a start, you can add the 5 to the other side.


Square root x+9=x+9

Square each of them

x+9=x^2+18x+81

Minus the first term.

x^2+17x+72=0

Factor that to (x+9)(x+8)

You tell me what is extraneous.

Answer 7

Im Ansering Your Answered Questions ;3